Michigan 2015: Round 2, Scramble 1
2015 07 12
Part of a 35 mean.

Scramble: F2 L D2 R' U2 R2 F2 R' B2 R2 D' F L' U' F2 D2 B' L' D2 L
Inverse: L' D2 L B D2 F2 U L F' D R2 B2 R F2 R2 U2 R D2 L' F2

Initial Attempt:

URB 2x2x2: U' B' R2 (3/3)
UDFR 2x2x3 + F cross piece: U' L2 U B2 D F' D' F D2 (9/12)
F2L pair: B L B2 (*) L' B U B2 U' (8/20)
F2L pair: (B2 L B L' B2 L B' L') (8/28)
All but 3 corners: (R' U' B' U B R) (6/34)

Solve corners at (*): F R2 F' L' F R2 F' L

Initial Solution: U' B' R2 U' L2 U B2 D F' D' F D2 B L B2 F R2 F' L' F R2 F' B U B2 U' R' B' U' B U R L B L' B2 L B' L' B2 (40)

Proceeded to try regular solving in the remaining time, and found with a cross on green (F):

F cross: F D U' B' R' B' R' (7/7)
F2L pair: U B' U' (3/10)
F2L pair: B U' B' U B' (5/15)
F2L pair: D' B' D2 B D' (5/20)
F2L pair: L B' L' B2 L B2 L' (7/27)
All but 3 corners: R' B' (%) U' B U R (6/33)

Solve corners at (%): B L B' R B L' B' R'

Note that cancelling the B' B, we are left with L' R' L, which cancels further.

Final Solution: F D U' B' R' B' R' U B' U' B U' B' U B' D' B' D2 B D' L B' L' B2 L B2 R' B' R B L' B' R' U' B U R (37)

I'm not sure if I noticed after the second F2L pair that I had a white cross with three F2L pairs solved.